PREDICTING RENDEMENT OF PRODUCT A REACTION
To
write a simple document, some reliable rules are needed to assess the direction
of a chemical reaction. And this judgment depends on several factors.
1. If free energy is
known, there is no problem in prediction.
2. If only known
enthalpy changes, predictions usually apply to ordinary temperatures are
cheaper reliable for higher temperatures.
3. If any of them can
be affected, the prediction is relatively simple and potential can be overcome
in the possibility of reaction in the absence of solvent.
4. If the equilibrium
constant is known, the relationship, G = - RH ln K gives free energy change, or
reaction at ordinary temperatures where the entropy changes are not expected to
be large, its relative strength in the reactants and the product can be estimated
as a guide for the course of the reaction. On this basis, we may use this rule:
Principle
1:
chemical reactions that occur with the bonds of electrons and electrons that
can be used together and allow the interaction of attraction between atoms.
The electron sac allows
it to be shared then it always goes on with energy changes. We may be able to
predict with confidence that all the atoms possessed or the outer orbital that
is emptied will join at a limit or capability below the average of either the same
element or different elements. Only the elements whose atoms are not
incorporated under normal conditions are the atoms that do not contain the
vacuum of their low external energy are called elements of iner or helium
classes.
Principle
2:
two elements can bond if the bonds formed are stronger than the average bond in
a free state.
For example, the
reaction between Cl2 and P. Cl2 in a stable state has an atomization energy of
29 kk / g atoms. The phosphorus atom is joined in a large set of molecules in
which each atom joins to three different covalent bonds where the heat or
atomisation strength is about 80kk / g of atoms. But it is easily disconnected
by PCl3 molecules. The heat of PCl3 formation is 26 kcal / ek. The difference
remains small, if all P and Cl2, whose atoms are separately like monoatomic
gases, will join together to form P (s) and Cl2 (g), or bind to form a PCl3
molecule.
When the atoms in each
compound retain the power to stay together, the compound form will produce very
strong strong binders if sufficiently polar. The same factor that affects
tungsten, for example, possesses very high atomisation heat which allows the
elements to form highly stable polar compounds, so that the energy lost in
separating the tungsten atoms is very large from the energy retrieval when it
joins with atoms such as halogens.
But when the elements
have the same electronegativity, the bond between the different elements of its
polarity will be weak and if the strength does not have to be very strong of
each element. For example, on the oxides of N it is not easily formed by
comparison which is not stable. The heat of formation follows NO = 21.6; NO2 =
8,1; N2O = 19.5; N2O3 = 20.00; N2O4 = 2,30; And N2O5 = 3.6 kcal / mol.
Principle
3:
Two molecules or ions tend to join if one pair of outer electrons can be shared
with atoms that have empty orbitals.
In reaction with a very
large atomic number known to the reaction type. This includes the linear
arrangement of all the molecules at the addition of components, the joining of
two simple components to form a component compound, and addition poli- lesation
(this type occurs with the addition of joint molecules, in the absence of
spiliting of some other products). This principle leads to a relatively stable
incorporation.
Example:
CaO
+ SO3 → CaSO4
CaO is a very stable
element, with the heat of atomization of 254 kcal / mol. However, having a
relatively high negative partial, so that O in CaO includes a good donor
potential. The three O bound to S, have less donor capacity, but enough to
allow S to be bound to CaO. As a result, the O negative binds to S forming SO4.
The heat of CaSO4 standard formation is 342 kcal / mol, in contrast to CaO
152kcal / mol, and SO3 95kcal / mol, otherwise summed only 247 kcal / mol.
In general, all
negative charged oxides are effective as donors which provide electrons for the
acceptor. The acceptor must have a high electron-electron attraction of the
positive atoms on the donor oxide. For example, Na (0.40 charge) in NaO2 to receive
electrons from O in CaO will be more attracted towards Ca because Ca has a load
of 0.57 so it has a strong appeal of Na. In addition, there will be no tone of
combining the two oxides as in N2O5 and SO3 because none of the O is negative
enough as an effective donor.
Finally, acknowledged
amphoteric oxides such as water may act as donor and acceptor in a reaction,
depending on the character of the other oxide. This reaction tends to occur
between halides (especially F) and sufides, with sulfides as metals and
non-metallic halides. For example, on the formation of halide and sulfide
complexes.
CaCl2 + 6 H2O →
CaCl2.6H2O
This type of reaction
depends on the ability of O on water to provide electrons, better than chloride
ions, with the previous assumption that O has more electron pairs than chloride
ions. Water molecules can bind to calcium ions. A similar reaction will not
proceed with kcl because K is of large size and weak nucleus load, so it is
less effective as electron-electron binder.
All synthesis and
adisin reactions take place with the reduction of entropy and therefore less
able to take place with the addition of temperature. At high temperatures where
the entropy goes beyond the enthalpy, it is more likely that a decomposition
reaction occurs
Principle
4:
An element tends to move to another of a compound if more than 1 polar bond is
produced.
This principle indirectly
describes the exchange of places between less active metals and very active
metals. For example, Na can replace Al instead of Cl and, more and more easily
replace H from water. However this only seems to imply a positive action from
Na. It is very accurate to recognize the tendency of the embodiment of chlorine
and O to have a high negative charge.
Principle
5:
A large trend is for metathesis reactions to aid the arrangement of most polar
bonds.
Some examples of
synthesis of organometallic compounds from halides with highly electronegative
metals and organometallic compounds with highly active metals.
HgCl2 + 2CH3MgCl → Hg
(CH3) + 2MgCl2
A very polar bond
exists between Mg and Cl, with charge Cl -0.17 in HgCl2 and -0.34 in MgCl2.
Hydrolysis of binary compounds is common, non-metals with low electronegative
nonmetals or metals.
NaH + H2O → 2NH3 + NaOH
Osigen is a element
with very large electronegative being very negative in OH - (- 0.67) than in
H2O (-0.25). The Mg-O bond is very polar.
Mg3N2 + 6H2O → 2NH3 +
3Mg (OH) 2
The type or reaction
that is often used as a prediction depends on:
- Synthesis: The direct
combination of elements or compounds
- Substitution:
Transfer of one element or compound from a complex by another element or
compound.
- Metathesis: Double
composition or exchange of pairs.
Synthesis
When all elements are
almost different in electronegativity, the bonds between two different elements
tend to be polar. Polar bonds tend to be stronger than non-polar bonds. The
bonds between the two different elements tend to be very strong on average or
bond in free elements. The heat of the formation of the binar compound is so
large that it is negative (exothermic), and in general the greater the
difference in the electronegativity and the bonded polarity results.
Substitution
The relationship
between bonding polarity and bond strength can be used only on general
estimates because it ignores other factors such as bonding arrangements and
bond lengths. Thus, this principle can be used entirely when other factors do
not vary widely. In particular, the keelektronegatifity of a unsure if large
will tend to have a high negative charge. In essence, the description of this
principle tends to the degree of electronegativity for the turn of the element
having the weak electronegativity of the component with the electron. The
degree of electronegativity strength can be seen at: I <Br <Cl <F. Or
by other conversion of hydride, sulfide, bromide, nitride, and iodod with heating
in water.
Metathesis
Metathesis is caused by
a polar bond which is usually the strongest bond. This should meet:
1) most polar bonds are
not necessarily very strong though often very strong,
2) the reaction does
not have to occur in the strongest bond or the most stable compound, because
sometimes free energy can be released when the compound is very stable and the
less stable compounds exchange charge to form two new compounds with intermediate
stability but above the average of the reactants . However, this rule is very
useful although limited to many types of chemical charge is very important.
In chemistry, yield, also referred to as reaction yield, is the amount of product obtained in a chemical reaction. The absolute yield can be given as the weight in grams or in moles (molar yield). The percentage yield (or fractional yield or relative yield), which serves to measure the effectiveness of a synthetic procedure, is calculated by dividing the amount of the obtained desired product by the theoretical yield (the unit of measure for both must be the same):
In chemistry, yield, also referred to as reaction yield, is the amount of product obtained in a chemical reaction. The absolute yield can be given as the weight in grams or in moles (molar yield). The percentage yield (or fractional yield or relative yield), which serves to measure the effectiveness of a synthetic procedure, is calculated by dividing the amount of the obtained desired product by the theoretical yield (the unit of measure for both must be the same):
The theoretical yield is the amount predicted by a stoichiometry calculation based on the number of moles of all reactants present. This calculation assumes that only one reaction occurs and that the limiting reactant reacts completely. However the actual yield is very often smaller (the percent yield is less than 100%) for several reasons:
- Many reactions are incomplete and the reactants are not completely converted to products. If a reverse reaction occurs, the final state contains both reactants and products in a state of chemical equilibrum.
- Two or more reactions may occur simultaneously, so that some reactant is converted to undesired by-products.
- Losses occur in the separation and purification of the desired product from the reaction mixture.
- Impurities are present which do not react
Example
Stoichiometry - rendemen?
Commercial acetic acid (97% C2H4O2) reacted with excess PCl5 will produce acetyl chloride (C2H3OCl). If the acetyl chloride produced is 75 g and the reaction efficiency (rendement) 78.2%, then the amount of acetic acid reacted is ..
Commercial acetic acid (97% C2H4O2) reacted with excess PCl5 will produce acetyl chloride (C2H3OCl). If the acetyl chloride produced is 75 g and the reaction efficiency (rendement) 78.2%, then the amount of acetic acid reacted is ..
The answer: 97% = 0.97
78.2% = 0.782
Rendmen = yield yield / theoretical rendement
0.782 = 75 / theoretical rendement
Theoretical rendemen = 75 / 0.782
Theoretical rendement = 95.9 gr
The resulting theoretical yield of acetic acid was 95.9 gr
Percent of acetic acid = 97% = 0.97
Mean, acetic acid = 05.9 x 0.97
Acetic acid = 93 grams
Thus, the amount of acetic acid treated was 93 grams
78.2% = 0.782
Rendmen = yield yield / theoretical rendement
0.782 = 75 / theoretical rendement
Theoretical rendemen = 75 / 0.782
Theoretical rendement = 95.9 gr
The resulting theoretical yield of acetic acid was 95.9 gr
Percent of acetic acid = 97% = 0.97
Mean, acetic acid = 05.9 x 0.97
Acetic acid = 93 grams
Thus, the amount of acetic acid treated was 93 grams

Can you give a simple example?
BalasHapusIts simple example on the reaction equation:
Hapus4Al + 3O2 → 2Al2O3, if Al = 1gr then how many predictions of ml O2?
Mol = 1/102 = 0.009 mol
Then the coefficient comparison:
Mol asked = coefficient asked / coefficient known x mol known
Mol O2 = 3/2 x 0.009 = 0.013
Then the volume stp = 0.013 x 22.4 = 0.3024 ml
what is recrystallization???please explainnn
BalasHapusRecrystallization is the purification of a solid from the mixture by recrystallizing the substance after it is dissolved in a suitable solvent. The principle of recrystallization is the difference of solubility between the substances to be purified by the solubility of the mixer / pollutant. Solutions that are exposed to each other, then the desired solution of the substance is crystallized by saturating it.
HapusCan you explain and give examples of the "if free energy is known, no problem in prediction." Factor?
BalasHapusThe reaction does not have to occur in the strongest or most stable bonds, because the free energy thing can be released at this time is very stable and the less stable the current to form two applied with intermediate stability but above the average of the reactants.
HapusSome examples of highly electronegative organic chemicals and organometallic compounds with highly active metals.
HgCl2 + 2CH3MgCl → Hg (CH3) + 2MgCl2
A very polar bond between Mg and Cl, with charge Cl -0.17 in HgCl2 and -0.34 in MgCl2. This binary hydrolysis is common, non metals with low electronegative nonmetals or metals.
NaH + H2O → 2NH3 + NaOH
Osigen is a element with very large electronegative being very negative in OH- (-0.67) rather than H2O (-0.25). The Mg-O bond is very polar.
Mg3N2 + 6H2O → 2NH3 + 3Mg (OH) 2
What is the product prediction of Cu + PbNO3 reaction?
BalasHapusPrediction of Cu + PbNO3 reaction product are:
HapusCu + 2PbNO3 → 2 Pb + Cu (NO3) 2
In general, all negatively charged oxides are effective as donors that provide electrons for acceptors. Acceptor must have high electron electron attraction of positive atoms on donor oxide. Explain why it can happen?
BalasHapusSince it is already a requirement,
HapusIn general, all negatively charged oxides are effective as donors which provide electrons for the acceptor. The acceptor must have a high electron electron attraction on the positive atoms of the donor oxide. For example, Na (0.40 charge) in NaO2 to receive electrons from O in CaO will be more attracted toward Ca because Ca has a load of 0.57 so it has a strong appeal of Na. In addition, there will be no merging of two oxides such as on N2O5 and SO3 because there is nothing negative enough to be an effective donor.
Finally, amphoteric acid-like saline as water may act as a donor and acceptor in a reaction, depending on the character of the other oxide.
How is an empty orbital?
BalasHapusMany transition metal complexes have a distinctive color. This means that there is absorption in visible light areas of electrons that are excited by visible light from the energy levels of complex molecular orbitals that are filled with electrons to an empty energy level. When the energy difference between the transitioning orbitals is called ΔΕ, the absorption frequency ν is given by the equation ΔΕ = hν. Electronic transitions produced by optical pumping (light) are roughly classified into two groups. If the two molecular orbitals that allow the transition have the main character d, the transition is called d-d transition or field transition, and the wavelength of the absorption depends very much on the field division. If one of the two orbitals has the main character of the metal and the other orbital has a ligand character, the transition is called the charge transfer. The transfers of charge transfers are classified on the transfer of metal charges to ligands (M) to ligand (L) charge-transfers (MLCT)) and the transfer of ligand to metal (LMCT) charges.
HapusWhat concepts do you get from the 5 principles?
BalasHapus1. The reaction tends to take place where bonding orbitals and commonly usable electrons are available and allow for interaction of attraction between atoms.
Hapus2. two elements can bond if the bonds formed are stronger than the average bond in a free state.
3. Two molecules or ions tend to join if one pair of outer electrons can be shared with atoms that have empty orbitals.
4. An element tends to move to another of a compound if more than 1 polar bond is produced.
5. A large trend is for metathesis reactions to aid the arrangement of most polar bonds.
Which is more reactive than this reaction ??? HgCl2 + 2CH3MgCl → Hg (CH3) + 2MgCl2
BalasHapusThe more reactive is Mg, because in the reaction only mg can react with water. In addition, the reactivity series is written backwards according to the standard electrode potential, also known as the "electrochemical series"
HapusGive me an example of, The relationship between bond polarity and bond strength
BalasHapusThe relationship between bonding polarity and bond strength can only be used as a rough estimate because it ignores other factors such as bond order and bond length.
Hapus1). An element which tends to move to another of a compound if its bond yield is more polar.
Indirectly, the principle that describes the displacement of a metal is less active by a more active metal. For example, sodium will replace aluminum from chloride and, much more easily, hydrogen from water. But this just seems to imply a positive, sodium action action. It may be more accurately acknowledged as a manifestation of the tendency of chlorine and oxygen to obtain a higher negative charge.
2). The main predisposition for metathetical reactions that may support the formation of the most polar bonds.
Some examples are the synthesis of organometallic compounds from more electronegative metal halides and more active metallic organometallic compounds.
HgCl2 + 2 CH3MgCl Hg (CH3) 2 + 2 MgCl2
The most polar bonds here are those between Mg and Cl, Cl charge becomes - 0.17 in HgCl2 and - 0.34 in MgCl2. Hydrolysis of binary compounds in general, from nonmetals with small electrons or metals.
NaH + H2O H2 + NaOH
Here oxygen is the most electronegative element and becomes much more negative at OH - (- 0.67) than in H2O (- 0.25). Here is the most polar Mg-O bond.
Mg3N2 + 6 H2O 2NH3 + 3 Mg (OH) 2
Two elements can bind to each other if bonds are formed stronger than the average bond in a free state. What is the meaning of the bonds contained in this sentence?
BalasHapusThe bonds referred to there are the results When the atoms in each compound maintain the power to stay together, so that the compound form will produce very strong bonds if sufficiently polar.
Hapuswhy it can be happen "two elements can bond if the bonds formed are stronger than the average bond in a free state"?
BalasHapusWhen the atoms in each compound retain the power to stay together, the compound form will produce very strong strong binders if sufficiently polar. The same factor that affects tungsten, for example, possesses very high atomisation heat which allows the elements to form highly stable polar compounds, so that the energy lost in separating the tungsten atoms is very large from the energy retrieval when it joins with atoms such as halogens.
HapusBut when the elements have the same electronegativity, the bond between the different elements of its polarity will be weak and if the strength does not have to be very strong of each element. For example, on the oxides of N it is not easily formed by comparison which is not stable. The heat of formation follows NO = 21.6; NO2 = 8,1; N2O = 19.5; N2O3 = 20.00; N2O4 = 2.30; And N2O5 = 3.6 kcal / mol.